2 1 8 × 3 2 7 = … …

$3\frac{2}{7}÷4\frac{1}{5}=\frac{23}{7}÷\frac{21}{5}=\frac{23}{7}\times \frac{5}{21}=\frac{{\displaystyle 115}}{{\displaystyle 147}}$

$4\frac{5}{6}÷3\frac{1}{2}=\frac{29}{6}÷\frac{7}{2}=\frac{29}{6}\times \frac{2}{7}=\frac{58}{42}=\frac{{\displaystyle 29}}{{\displaystyle 21}}$

$7\frac{6}{3}-7\frac{6}{7}=\frac{27}{3}-\frac{55}{7}=\frac{189}{21}-\frac{165}{21}=\frac{189-165}{21}=\frac{24}{21}=\frac{8}{7}$