3 2 7 ÷ 4 1 5 = … …

$4\frac{5}{6}÷3\frac{1}{2}=\frac{29}{6}÷\frac{7}{2}=\frac{29}{6}\times \frac{2}{7}=\frac{58}{42}=\frac{{\displaystyle 29}}{{\displaystyle 21}}$

$7\frac{6}{3}-7\frac{6}{7}=\frac{27}{3}-\frac{55}{7}=\frac{189}{21}-\frac{165}{21}=\frac{189-165}{21}=\frac{24}{21}=\frac{8}{7}$

$9\frac{3}{4}-5\frac{3}{5}=\frac{39}{4}-\frac{28}{5}=\frac{195}{20}-\frac{112}{20}=\frac{195-112}{20}=\frac{{\displaystyle 83}}{{\displaystyle 20}}$